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Apple App Development with Swift Certified User Exam App-Development-with-Swift-Certified-User Prüfungsfragen mit Lösungen (Q13-Q18):

13. Frage
Complete the code that will add the BlueView to the NavigationStack and present the RedView modally.

|Complete the code by typing in the boxes.

Antwort:

Begründung:
NavigationLink, .sheet
Explanation:
This question falls under View Building with SwiftUI , specifically the domain covering multi-view apps with navigation stacks, links, and sheets . The first blank must be NavigationLink because SwiftUI uses a navigation link inside a NavigationStack to push or present a destination view as part of the navigation hierarchy. Apple's documentation states that people tap or click a NavigationLink to present a view inside a NavigationStack or NavigationSplitView. That matches the first code section, where tapping " Show Blue View " should navigate to BlueView().
The second blank must be .sheet because the code uses isPresented: $showRedView, which is the standard SwiftUI sheet modifier for modal presentation controlled by a Boolean binding. Apple documents sheet (isPresented:onDismiss:content:) as the modifier to use when you want to present a modal view when a Boolean becomes true. Since the button toggles showRedView, SwiftUI presents RedView() modally as a sheet.
So the completed structure is effectively:
NavigationLink( " Show Blue View " ) {
BlueView()
}
sheet(isPresented: $showRedView) {
RedView()
}
This directly aligns with SwiftUI navigation and modal presentation patterns in the App Development with Swift objective domains.

14. Frage
Review the code.

When entered into the TextField, which number will display a blue canvas on the SecondView?

A. 0
B. 1
C. 2
D. 3

Antwort: D

Begründung:
This question belongs to View Building with SwiftUI , especially the domain on creating multiple views to implement app logic and sharing values between views. In FirstView, the value typed into the TextField is stored in number, which is a String. When the NavigationLink is tapped, the code passes Int(number) ?? 0 into SecondView. In Swift, converting a string to an integer with Int(...) uses an optional initializer, which means it returns an optional value and will produce nil if the string cannot be converted. The ?? 0 nil- coalescing operator then supplies 0 if conversion fails.
Inside SecondView, the body is:
Color(passedNumber == 3 ? .blue : .red)
This uses the ternary conditional operator. If passedNumber equals 3, the displayed color is blue; otherwise, it is red. Therefore, entering 3 into the TextField causes Int(number) to become 3, which makes the condition passedNumber == 3 true and displays a blue canvas. Any other listed number results in red.
So the correct answer is A. 3 . This matches the SwiftUI pattern of taking user input, converting it to the needed type, passing it into another view, and rendering UI conditionally based on that value.

15. Frage
Review the code.
struct ContentView: View {
let fruits = [ " Apple " , " Banana " , " Kiwi " ]
var body: some View {
List(fruits, id: .self) { fruit in
Text(fruit)
.font(.headline)
.padding()
}
}
}
Which of the following statements is true about the code?

A. The List view is using the fruits array to display the contents as individual rows.
B. The id: .self in the List view should be rewritten as id: /self
C. The id: .self in the List view is not necessary and may be omitted.
D. KeyPaths are used here to extract the font and padding properties dynamically.

Antwort: A

Begründung:
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question belongs to View Building with SwiftUI , especially the domain covering List Views to iterate through collections . In the code, fruits is an array of strings, and the List initializer is being used to create one row for each item in that collection. Apple's SwiftUI documentation explains that List can present rows from a collection of data, and when the data elements are not supplied through a type that already provides identity, you can provide an id key path so SwiftUI can uniquely identify each row. Here, id: .self tells SwiftUI to use each string value itself as the identifier.
Option D is therefore the correct statement because the List is clearly rendering the contents of the fruits array as separate rows, and each row shows a Text(fruit) view. Apple's app development tutorials describe List as a container view that displays rows of data arranged in a single scrollable column, which matches exactly what this code is doing.
Option A is false because for an array of String values in this form, id: .self is used to identify each row.
Option B is false because the key path is not related to .font(.headline) or .padding(); those are standard view modifiers, not dynamic property extraction in this example. Option C is false because Swift key-path syntax uses a backslash, as in .self, not /self. Apple's KeyPath documentation shows that Swift key paths use the backslash form.

16. Frage
When you press ' Show Button ' on your app. a modal View appears.
Complete the code by selecting the correct option from each drop-down list.
Note: You will receive partial credit for each correct answer.

Antwort:

Begründung:

Explanation:

This question belongs to View Building with SwiftUI , specifically the domain on creating a multi-view app with navigation stacks, links, and sheets .
To present a modal view in SwiftUI when a Boolean state changes, the correct modifier is .sheet . The matching sheet API for a Boolean binding is:
sheet(isPresented: $showInfo) {
// modal content
}
So the first blank must be .sheet , and the second blank must be (isPresented: .
The logic works like this:
* @State stores the local Boolean that controls presentation.
* Pressing the button calls showInfo.toggle(), changing the value from false to true.
* When that Boolean becomes true, the .sheet(isPresented:) modifier presents the modal view.
* When the modal is dismissed, SwiftUI updates the Boolean back as needed.
There is also a typing issue in the screenshot: the state variable appears as ShowInfo, while the button and binding use showInfo. Swift is case-sensitive, so those names must match. The corrected code should use the same identifier consistently, such as:
@State var showInfo = false
Therefore, the correct dropdown selections are:
sheet
(isPresented:

17. Frage
Review the code snippet and identify what happens when the program is executed.

A. The for loop prints all the menu items in the array.
B. Only menu items including " Burger " . " Chicken " . " Pasta " . " Salad " are printed.
C. Only menu items including " Pizza " . " Burger " , " Chicken " . " Pasta " . " Salad " are printed.
D. Only menu items including " Burger " . " Chicken " . " Pasta " . " SaJad " . " Steak " are printed.

Antwort: B

Begründung:
This question belongs to Swift Programming Language , specifically the objectives covering arrays , loops
, and range operators . The array has 6 elements, so menuItems.count is 6. The loop uses the half-open range operator:
for index in 1.. < (menuItems.count - 1)
That becomes:
for index in 1.. < 5
In Swift, the half-open range operator a.. < b includes the lower bound but does not include the upper bound.
So this loop runs with index values 1, 2, 3, 4, not 0 and not 5.
Array subscripting uses those indexes to print:
* menuItems[1] # " Burger "
* menuItems[2] # " Chicken "
* menuItems[3] # " Pasta "
* menuItems[4] # " Salad "
That means " Pizza " at index 0 is skipped, and " Steak " at index 5 is also skipped. Swift arrays use zero- based indexing, and count returns the number of elements in the array.
Therefore, the program prints only " Burger " , " Chicken " , " Pasta " , and " Salad " , so the correct answer is A .

18. Frage
......

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